Electron Configuration Of Oxygen In Excited State. Based on the periodic table, o is atomic number 8, which means it has 8 electrons. Since 1s can only hold two electrons the next 2 electrons for o go in the 2s orbital.
It is filling in the normal order; The 4s electrons are at a lower energy level than 3d electrons Neither, the oxygen atom is in the ground state.
Since 1s can only hold two electrons the next 2 electrons for o go in the 2s orbital.
Like for a if there were two up arrows in two separate boxes in the 2p orbitals it would be in its ground state. Provide the corresponding electron configuration (a), identify the element (b), and then provide the ground state electron configuration for an atom of that element (c). The electron configuration of an exited state of oxygen is 1s2 2s2 2p3 3s1 but my question is why it is not 1s2 2s1 2p5 how to determine which electron in which orbital is move to the another? Neither, the oxygen atom is in the ground state.